Question

Question 14
in a rectangular plot, 5 square flower beds of side (x+2) metres each have been laid (see the
figure). Find the total cost of fencing the flower beds at the cost of Rs. 50 per 100 metres..​

Answer 1

The total cost for all five beds is 10(x+2) rupees.

Step-by-step explanation:

We know that;

• perimeter of square = $4 \times (length \ of \ a \ side)$

So, we can write as,

• perimeter of 1 square bed = 4(x+2)
• perimeter of 5 square beds =$5 \times 4(x+2)$

                                                       = 20(x+2)

Since it is given that the rate for fencing, Rs. 50 per 100 meters.

• Cost for 100 m = 50 Rupees

• Cost for 1 m =$\dfrac{50}{100}$

                             = 0.5 Rupees

Therefore, the cost for 20(x+2) m =$0.5 \times 20(x+2)$ rupees

• Required total cost = 10(x+2) rupees
• Thus, the total cost for all five beds is 10(x+2) rupees.

Answer 2

The total cost for all five beds is 10x+20 rupees.

Step-by-step explanation

perimeter of square =4 * side

perimeter of 1 square bed=4(x+2)

perimeter of 5 square beds =5*4(x+2)

                                               = 20(x+2)

Since it is given that the rate for fencing, Rs. 50 per 100 meters.

Cost for 100 m = 50 Rupees

Cost for 1 m =50/100 Rupees

                    = 0.5 Rupees

Therefore, the cost for 20(x+2) m = 0.5*20(x+2) rupees

                                                        = 10(x+2)

                                                        = 10x+20

Required total cost = 10x+20 rupees

Thus, the total cost for all five beds is 10x+20 rupees.