Question

question 15 answer any One​

Answer 1

Answer:

the protoelectrons will be emitted.

Explanation:

The Einstein's equation for photoelectric effect is KE  

max   = λ hc  −   λ0

​  

 

hc

​  

 where KE  

max

​  

= maximum kinetic energy of photoelectrons , h= Planck's constant, c= velocity of light, λ= wavelength of incident light and λ  

0

​  

= threshold wavelength.

For emission of photoelectrons , $$KE_{max}>0$$

So, $$\dfrac{hc}{\lambda}-\dfrac{hc}{\lambda_0}>0$$

or $$\dfrac{hc}{\lambda}>\dfrac{hc}{\lambda_0}$$

or $$\dfrac{1}{\lambda}>\dfrac{1}{\lambda_0}$$

or $$\lambda<\lambda_0$$

Since $$\lambda=2000 A^o <\lambda_0=3000 A^o$$ so the photoelectrons will be emitted.