Question

Question 16. Please solve.

Answer 1

Answer:

Step-by-step explanation:

Since x+ a is a factor of the polynomial

Therefore , x+a =0

a= -x

x-1 is also factor of p(x)

So, x-1=0

or x=1..................... (1)

Substituting the. Value of a in the polynomial

p(x)= 0

or p(x)= x^3 + 2x^2 + (-x)x +b =0

or p(x) = x^3 +2x^2 -x^2 +b= 0

or p(x) = x^3 +x^2 +b =0

Substituting the value of x from eqn.... 1

p(x) = 1^3 +1^2 +b =0

p(x) = 2+ b =0

p(x)= b = -2

Since, b=-2

So, 1^3+ 2(1)^2+ a(1) + (-2) =0

or 1+2 -2 +a =0

or a= -1

Therefore answer is option 3.... a= -1

Answer

It takes some time to type mathematical letters in mobile so I hope u understood this.