Computer Science, asked by sayampaul, 9 months ago

Write a program to input any two no.s and print their LCM and HCF using user defined functions in java method not in c programming

Answers

Answered by sweta7570
0

C programming code

#include <stdio.h>

int main() {

 int a, b, x, y, t, gcd, lcm;

 printf("Enter two integers\n");

 scanf("%d%d", &x, &y);

 a = x;

 b = y;

 while (b != 0) {

   t = b;

   b = a % b;

   a = t;

 }

 gcd = a;

 lcm = (x*y)/gcd;

 printf("Greatest common divisor of %d and %d = %d\n", x, y, gcd);

 printf("Least common multiple of %d and %d = %d\n", x, y, lcm);

 return 0;

Download HCF and LCM program.

Output of program:

HCF and LCM c program

C program to find hcf and lcm using recursion

#include <stdio.h>

long gcd(long, long);

int main() {

 long x, y, hcf, lcm;

 printf("Enter two integers\n");

 scanf("%ld%ld", &x, &y);

 hcf = gcd(x, y);

 lcm = (x*y)/hcf;

 printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);

 printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);

 return 0;

}

long gcd(long a, long b) {

 if (b == 0) {

   return a;

 }

 else {

   return gcd(b, a % b);

 }

}

C program to find hcf and lcm using function

#include <stdio.h>

long gcd(long, long);

int main() {

long x, y, hcf, lcm;

 printf("Enter two integers\n");

 scanf("%ld%ld", &x, &y);

 hcf = gcd(x, y);

 lcm = (x*y)/hcf;

 printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);

 printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);

 return 0;

}

long gcd(long x, long y) {

 if (x == 0) {

   return y;

 }

 while (y != 0) {

   if (x > y) {

     x = x - y;

   }

   else {

     y = y - x;

   }

 }

 return x;

}long x, y, hcf, lcm;

 printf("Enter two integers\n");

 scanf("%ld%ld", &x, &y);

 hcf = gcd(x, y);

 lcm = (x*y)/hcf;

 printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);

 printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);

 return 0;

}

long gcd(long x, long y) {

 if (x == 0) {

   return y;

 }

 while (y != 0) {

   if (x > y) {

     x = x - y;

   }

   else {

     y = y - x;

   }

 }

 return x;

}long x, y, hcf, lcm;

 printf("Enter two integers\n");

 scanf("%ld%ld", &x, &y);

 hcf = gcd(x, y);

 lcm = (x*y)/hcf;

 printf("Greatest common divisor of %ld and %ld = %ld\n", x, y, hcf);

 printf("Least common multiple of %ld and %ld = %ld\n", x, y, lcm);

 return 0;

}

long gcd(long x, long y) {

 if (x == 0) {

   return y;

 }

 while (y != 0) {

   if (x > y) {

     x = x - y;

   }

   else {

     y = y - x;

   }

 }

 return x;

}

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