Question 17 Tick the correct answer and justify: In ΔABC, AB = 6.3^0.5 cm, AC = 12 cm and BC = 6 cm. The angle B is: (A) 120° (B) 60° (C) 90° (D) 45°
Class 10 - Math - Triangles Page 151
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Answered by
27
Given :
AB = 6√3cm
AC= 12 cm
BC = 6 cm
In ∆ABC
Now, AB²+ BC²= AC²
(6√3)²+ 6² = 12²
36×3 + 36 = 144
108+36= 144
144= 144
The given ∆ ABC satisfies the Pythagoras theorem.
Hence , the ∆ is a right angled at B .
Angle B= 90°
____________________________
Hence , the correct option is C .
____________________________
Hope this will help you.....
AB = 6√3cm
AC= 12 cm
BC = 6 cm
In ∆ABC
Now, AB²+ BC²= AC²
(6√3)²+ 6² = 12²
36×3 + 36 = 144
108+36= 144
144= 144
The given ∆ ABC satisfies the Pythagoras theorem.
Hence , the ∆ is a right angled at B .
Angle B= 90°
____________________________
Hence , the correct option is C .
____________________________
Hope this will help you.....
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Answered by
11
Given that, AB = 6√3 cm, AC = 12 cm, and BC = 6 cm
We can observe that
AB2 = 108
AC2 = 144
And, BC2 = 36
AB2 + BC2 = AC2
The given triangle, ΔABC, is satisfying Pythagoras theorem.
Therefore, the triangle is a right triangle, right-angled at B.
∴ ∠B = 90°
We can observe that
AB2 = 108
AC2 = 144
And, BC2 = 36
AB2 + BC2 = AC2
The given triangle, ΔABC, is satisfying Pythagoras theorem.
Therefore, the triangle is a right triangle, right-angled at B.
∴ ∠B = 90°
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