Question

Question 19
एक समांतर चतुर्भुज कि एक भुजा और संगत ऊंचाई
क्रमश: 5cm और 3cm है। समांतर चतुर्भुज का क्षेत्रफल
ज्ञात कीजिये ?A side and corresponding heighto
a parallelogram are 5cm and 3cm respectively.
Find the area of the parallelogram?​

Answer 1

Answer:

• Area of the parallelogram is 15 cm².

Step-by-step explanation:

Given that:

• Base of a parallelogram = 5 cm
• Height of a parallelogram = 3 cm

To Find:

• Find the area of the parallelogram?

Formula used:

• Area of a parallelogram = Base × Height

Finding the area of the parallelogram:

⟶ Area = 5 × 3

⟶ Area = 15

∴ Area of the parallelogram = 15 cm²

Answer 2

${\pmb{\underline{\sf{ Required \ Solution ... }}}}$

• Side of a Paralellogram = 5 cm
• Corresponding Height of Paralellogram = 3cm

As We know that we can find the Area of the Paralellogram using their side and corresponding Height as:-

$\circ \ {\pmb{\underline{\boxed{\sf\red{ Area_{(Paralellogram)} = Base \times Height }}}}}$

Now, After substituting values in formula to get desired results as:-

$\circ \ {\pmb{\underline{\sf{ According \ to \ Question: }}}} \\ \\ \colon\implies{\sf{ 5 \times 3 }} \\ \\ \colon\implies{\underline{\boxed{\sf{ 15 \ cm^2 }}}}$

Hence,

${\pmb{\underline{\sf\green{ The \ Area \ of \ Paralellogram \ is \ 15 \ cm^2 . }}}}$

$\\ {\pmb{\underline{\sf{More \ to \ Know ... }}}}$

$\circ \ {\boxed{\sf\green{Area_{(Paralellogram)} = ab \ sin( \theta ) }}}$

• a and b are the length of parallel sides and theta is the angle b/w the sides of the parallelogram.

$\circ \ {\boxed{\sf\green{Area_{(Using \ Diagonals)} = \dfrac{1}{2} \times d_1 \times d_2 sin( \theta ) }}}$

• ${\sf{ d_1}}$ and ${\sf{ d_1}}$ are Diagonals and theta is an angle of the Paralellogram.