question 19 i want answer
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ananya56:
its physics question
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firstly write
Distance travelled,s=Area of trapezium 0ABC
s= (sum of parallel sides) × height
~~~~~~~~~~~~~~~~~~~~~~~~~~
2
s= (OA +CB)×OC
~~~~~~~~~~~~~
2
NOW,
OA+CB= u + v and OC=t
put,
s=(u+v) t upon 2
v=u+at
t=(v-u) upon a
putting value of t,
s=(u+v)×(v-u) upon 2a
2as =v^2 -u^2
hence derived.
Distance travelled,s=Area of trapezium 0ABC
s= (sum of parallel sides) × height
~~~~~~~~~~~~~~~~~~~~~~~~~~
2
s= (OA +CB)×OC
~~~~~~~~~~~~~
2
NOW,
OA+CB= u + v and OC=t
put,
s=(u+v) t upon 2
v=u+at
t=(v-u) upon a
putting value of t,
s=(u+v)×(v-u) upon 2a
2as =v^2 -u^2
hence derived.
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ur welcome dear
u r beginner
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