Question

Question 19. sin290 - sec260 +
cot245 = ? *


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Answer 1

Answer:

$sin^{2}90-sec^{2}60+cot^{2}45=-4$

Step-by-step explanation:

$sin^{2}90-sec^{2}60+cot^{2}45=?\\(1)^{2}-(2)^{2}+(1)^{2}=?\\1-4+1\\1-5\\-4$

Ans= -4

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