Question

Question.1Find the 37th term of the AP 6, 7(3/4),9(1/2),11{1/4}
If any problem photo is provided ​

Answer 1

Answer:33

Step-by-step explanation:

Answer 2

Given :-

• $\sf A.P = 6.7\dfrac{3}{4} . 9\dfrac{1}{2} . 11\dfrac{1}{4}$

• 1st term = 6

To Find :-

• $\sf 37th \: term( a_{37}) = ?$

Solution :-

$\qquad\leadsto\quad\sf \green{Common \: difference = a_{2} - a_{1}}$

$\qquad\leadsto\quad\sf Common \: difference = \frac{31}{4} - 6$

$\qquad\leadsto\quad\sf Common \: difference = \frac{31 - 24}{4}$

$\qquad\leadsto\quad\sf \green{Common \: difference = \frac{7}{4}}$

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$\small\underline{\pmb{\sf \:According \: to \: the \: question :-}}$

$\qquad\leadsto\quad \sf \pink{ a_{37} = a + (n - 1)d}$

$\qquad\leadsto\quad\sf a_{37} = 6 + (37 - 1) \times \frac{7}{4}$

$\qquad\leadsto\quad\sf a_{37} = 6 + 36 \times \frac{7}{4}$

$\qquad\leadsto\quad\sf a_{37} = 6 + 63$

$\:\:\:\:\:\:\:\:\leadsto\:{\underline{\boxed{\frak{\pink{ a_{37}= 69}}}}}\:\bigstar$

$\therefore\:\underline{\textsf{37th term of think A.P is \textbf{69 }}}.$