Question

the molality of glucose when 0.015 moles of glucose dissolved in 30 g of water​

Answer 1

Answer:

0.0005 m

Explanation:

0.0015 divided by 3 =0.0005 m

Answer 2

Molality of glucose =  0.5 mol/kg

Explanation:

Given: 0.015 moles of glucose dissolved in 30g of water.

Find: Molality of glucose

Solution:

Molar mass of water (H2O) = 2 + 16 = 18 g

Moles of water = 30/18 = 1.66  

Molar mass of glucose (C₆H₁₂O₆) = 6*12 + 12 + 6*16 = 180 g

Moles of glucose = 0.015

Molality = moles of solute * 1000/ Mass of solvent

Molality = 0.015 * 1000 / 30

Molality = 0.5 mol/kg