Question

Question 2.32 Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit.

Class XI Structure of Atom Page 67

Answer 1

According to Bohr's model of H - atom,
angular momentum of an electron is integral of h/2π . where h is Plank's constant .
e.g., mvr = nh/2π
=> 2πr = n (h/mv) -------(1)


now, according to De - broglie's wavelength,
λ = h/mv ----------------(2)

put equation (2) in equation (1)

2πr = nλ
Therefore, the circumference of the Bohr's orbit for H - atom is an integral multiple of the De - broglie's wavelength associated with the electron revolving around the orbit .