Question 2. An object moves along the grid through points A, B, C, D, E, and F as shown below. The side of square tiles measures 0.5 km.
a) Calculate the distance covered by the moving object.
b) Find the magnitude of the displacement of the object.
Answers
SOLUTION :-
a) The distance covered by the moving object is calculated as follows:
AB + BC + CD + DE + EF
3 + 1 + 1.5 + 0.5 + 0.5 = 6.5 km
The distance covered by the moving object is 6.5 km.
b) The initial point is A and the final point is F, hence the magnitude of the displacement is equal to the distance AF which is calculated by applying Pythagora’s theorem to the triangle AHF as shown in the attachment.
Applying the Pythagorean formula, we get
AF²=AH²+HF²
Substituting the formula, we get
AF² = (0.5×4)² +(0.5×3)²
AF² = 6.25
AF = √6.25
.°. AF = 2.5 km.
The magnitude of displacement is 2.5 km.
SOLUTION:-
a) The distance covered by the moving object is calculated as follows:
AB + BC + CD + DE + EF
3 + 1 + 1.5 + 0.5 + 0.5 = 6.5 km
The distance covered by the moving object is 6.5 km.
b) The initial point is A and the final point is F, hence the magnitude of the displacement is equal to the distance AF which is calculated by applying Pythagora’s theorem to the triangle AHF as shown in the attachment.
Applying the Pythagorean formula, we get
AF²=AH²+HF²
Substituting the formula, we get
AF² = (0.5×4)² +(0.5×3)²
AF² = 6.25
AF = √6.25
.°. AF = 2.5 km.
The magnitude of displacement is 2.5 km.
