question 2 and 3 answer
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answer 2.
volume of room=area of floor x height
378 = 84 x height
height = 378/84
= 4.5 m
answer 3.
we know that the diagonals of rohmbus bisect each other at 90 degree.
so, 16/2=8cm
and 12/2=6cm
now using pythagoras
(8)^2 + (6)^2 = (Hypotenus)^2
hypotenus = 10cm
so each side measures 10 cm
volume of room=area of floor x height
378 = 84 x height
height = 378/84
= 4.5 m
answer 3.
we know that the diagonals of rohmbus bisect each other at 90 degree.
so, 16/2=8cm
and 12/2=6cm
now using pythagoras
(8)^2 + (6)^2 = (Hypotenus)^2
hypotenus = 10cm
so each side measures 10 cm
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