Question

Question 2 Find the product by suitable rearrangement: (a) 2 × 1768 × 50 (b) 4 × 166 × 25 (c) 8 × 291 × 125 (d) 625 × 279 × 16 (e) 285 × 5 × 60 (f) 125 × 40 × 8 × 25

Class 6 - Math - Whole Numbers Page 40

Answer 1

Finding product by suitable rearrangement

a) 2 × 1768 × 50

= (2×50)× 1768

= 100× 1768

= 1768
= 176800

b) 4 × 166 × 25

=( 4× 125) × 166

= 100×166
= 16600

c) 8 × 291 × 125

= (8 × 125)× 291

= 1000×291
= 291000

d) 625 × 279 × 16

= (625 × 16)×279

= 10000× 279

= 2790000

e) 285 × 5 × 60

= 285 × (5 × 60 )

= 285× 30

= 85500

f) 125 × 40 × 8 × 25

= (125×8) × (40×25)

= 1000 × 1000

= 1000000
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Hope this will help you....

Answer 2

Finding product by suitable rearrangement

a) 2 × 1768 × 50

= (2×50)× 1768

= 100× 1768

= 1768

= 176800

b) 4 × 166 × 25

=( 4× 125) × 166

= 100×166

= 16600

c) 8 × 291 × 125

= (8 × 125)× 291

= 1000×291

= 291000

d) 625 × 279 × 16

= (625 × 16)×279

= 10000× 279

= 2790000

e) 285 × 5 × 60

= 285 × (5 × 60 )

= 285× 30

= 85500

f) 125 × 40 × 8 × 25

= (125×8) × (40×25)

= 1000 × 1000

= 1000000

_____________________________

Hope this will help you....