What weight of sodium nitrate will separate when a saturated solution containing 50 g of water is cooled from 50 degree celcius to 30 degree celcius? the solubility of NaNO3at 50 degree celcius& 30 degree celcius is 114 g & 86 g respectively .
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The solubility of NaNO₃ at 50°C= 114 g
Water required= 100g
Hence, For 50g of water the required NaNO₃= 114/2 = 57g
Similarly, solubility of NaNO₃ at 30°C= 86 g
hence, or solution of 50g water= 86/2 = 43 grams of NaNO3.
Hence, when a saturated solution of sodium nitrate at 30°C is left to cool, then 43 grams of solid sodium nitrate will separate out.
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