Question

Question 2. How many term are these in the AP 7,13,19,...........205?

Answer 1

Answer:

given : a = 7

Tn = 205

d = 6 ( 19 - 13 = 6 , 13 -7 = 6)

Tn = a + (n-1)d

205 = 7 + ( n-1) 6

205 = 7 + 6n - 6

204 = 6n or

6n = 204

n = 204 / 6

:. n = 34.

I hope it works

from Patna

Answer 2

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

$= >n = 34$

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

How many term are these in the AP 7,13,19,...........205?

$\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$

• Given sequence is 7,13,19,...,205

• Given sequence is 7,13,19,...,205The first term a=7 and

• The common difference d=13−7=6

• The last term is 205

• Let the last term be the nth term.

We know that the nth term of the arithmetic progression is given by -

$= > a+(n−1)d$

$= > a+(n−1)d=205$

$= > 7+(n−1)×(6)=205</p><p></p><p></p><p>$

$= > 7− \: 6+6n=205</p><p></p><p></p><p>$

$= > 1+6n=205</p><p></p><p></p><p>$

$= > 6n=205−1$

$= > 6n = 204$

$= >n = \frac{204}{6}$

$= > n = 34$

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The number of terms in the given sequence is 34