Question

Question 20 and pls pls pls pls answer fast

Answer 1

Let,

/_DBC = x°

Now, it is given that,

∆ ABC is a right - angled triangle.

•°•

/_ABC = 90°

/_DBC + /_DBA = 90° [ as /_ABC = /_DBC + /_DBA]

x° + /_1 = 90°

/_1 = ( 90 - x )° __________( 1 )

In ∆ DBC, /_BDC = 90°

Also,

/_DBC + /_BDC + /_DCB = 180° [ Angle Sum Property ]

x° + 90° + /_2 = 180°

/_2 = 180° - 90° - x°

/_2 = ( 90 - x )° ___________( 2 )

From ( 1 ) and ( 2 )

/_1 = /_2

Hence, proved

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