Question 20:
In the circuit diagram given below, the current flowing across 5 ohm resistor is 1 amp. Find the current flowing through the other two resistors.
Lakhmir Singh Physics Class 10
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it is given that, current through 5Ω resistor is 1amp.
all the given resistors are joined in parallel combination.
and we know, potential difference across all resistors will be same if these are joined in parallel combination.
so, potential difference across 5Ω resistor , V= 5Ω × 1ohm = 5volts
now current through 10Ω resistor = V/R = 5volts/10Ω = 0.5Amp
current through 4Ω resistor = V/R'
= 5volts/4Ω = 1.25 amp
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Answer:
1.25 ampere is the current through 4 ohm resistance and 0.5 ampere current flows through the 10 ohm resistance
Explanation:
R1 = 5 ohm
R2 = 4 ohm
R3 = 10 ohm
I(1)[across R1]=1 amps
I(2)[across R2]=? amps
I(3)[across R3]=? amps
Now
V=I×R
V1=I(1)×R1=(1×5)v=5v
I(2)=V1/R3=5/10=0.5amps
I(3)=V1/R3=5/4=1.25amps
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