Question

QUESTION 21 TO 24 ARE OF 6 MARKS EACH
Question 21 find the least number which when divided by 12, 16, and 36 leaves a
remainder 7 in each case.​

Answer 1

Answer:

Least number when divided by 12,16,24,36 and leaves remainder 0

=LCM of 12,16,24,36

So,LCM leaves remainder 0

So,Required number will be 7 more than LCM

∴ Required number=LCM+7

Factors of 12=2×3×2

Factors of 16=2×2×2×2

Factors of 24=2×2×2×3

Factors of 36=2×2×3×3

∴ LCM=2×2×2×2×3×3=16×9=144

So,Required number=LCM+7=144+7=151