Question 22. Chapter- Determinants. ISC Class
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Please see the attachment
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nikhil1331:
Thank You. Thanks a lot. Can you please elaborate line 3 and 4?
take common a-c from first row and find determinent using first column.
i cant understand Step 3 also
from step 2 subtract row 2 from row 1
in the second and third step, (a^2+ab+b^2) - (b^2+bc+c^2) = (a^2+ab+b^2-b^2-bc-c^2.
but you have written (a-c)(a+b+c) which means (a^2+ab+ac-ac-bc-c^2)., Why and how?
(a square - c square) +b(a-c) =(a+c) (a-c) +b(a-c) =(a-c) (a+b+c)
wow!!
thanks a lot for your help
solved finally!
Answered by
1
You want answers of all the three??
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i mean, How did you bring two extra abc?
if u multiply
(c-a) with (ab+bc+ca) u will get
that ans
ac^2 +bc^2-a^2b -a^2c
u will get thus
this
oye, I need some help.
sayy
sorry was busy
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