Physics, asked by Brijeshkumar2707, 1 year ago

Question 25:
Calculate the momentum of the following :
(a) an elephant of mass 2000 kg moving at 5 m/s
(b) a bullet of mass 0.02 kg moving at 400 m/s


Lakhmir Singh Physics Class 9

Answers

Answered by snehadlakha
68

Momentum,p = mv


a) m = 2000 kg


v = 5 m/s


p = mv = 2000 × 5 = 10000 kgm/s


a) m = 0.02 kg


v = 400 m/s


p = mv = 0.02 × 400 = 8 kgm/s.

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Answered by Tulsi4890
0

The momentum(p₁) of the elephant is 10000 kgm/s.

The momentum(p₂) of the bullet is 8 kgm/s.

Given:

(a) an elephant of mass 2000 kg moving at a velocity of 5 m/s

(b) a bullet of mass 0.02 kg moving at a velocity of 400 m/s

To Find:

The momentum of the given data.

Solution:

We are required to find the momentum of the given data.

The momentum formula is given as

Momentum, p = mv

a) Elephant mass(m₁) = 2000 kg

velocity(v₁) = 5 m/s²

Momentum, p₁ = m₁v₁  ----------(1)

Substitute the values of m₁ and v₁ in the equation(1) we get

p₁ = 2000×5

p₁ = 2000×5

p₁ = 10000 kgm/s²

Therefore, The momentum(p₁) of the elephant is 10000 kgm/s.

b) Bullet mass(m₂) = 0.02 kg

velocity(v₂) = 400 m/s

Momentum, p₂ = m₂v₂  ----------(2)

Substitute the values of m₂ and v₂ in equation(2) we get

p₂ = 0.02×400

p₂ = 0.02×400

p₂ = 8 kgm/s

Therefore, The momentum(p₂) of the bullet is 8 kgm/s.

#SPJ2

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