Question

Question(26)
An automobile weighing 4000 kg
climbs up a hill that rises 1 in 20 m
of its length at the rate of 54 kmph.
Neglecting friction, the minimum
power developed by the engine is​

Answer 1

Answer:

Thanks for free points......

Answer 2

Answer:

power = 29400W

Explanation:

mass = 4000kg

sinteta = 1/20

velocity= 54×5/18 m/s= 15m/s

power = force × velocity

force = mgsinteta

p = mgsinteta ×v

p= 4000(9.8)×1/20×15

p = 29400W