Question

Question 27:
In the circuit shown below, the voltmeter reads 10 V.

(a) What is the combined resistance ?
(b) What current flows ?
(c) What is the p.d. across 2 Ω resistor ?
(d) What is the p.d. across 3 Ω resistor ?

Lakhmir Singh Physics Class 10

Answer 1

Answer:

a) 5ohm

b) 2amp

c) 4V

d) 6V

Explanation:

Although the above given question has not given the circuit, but from the question we can conclude that the voltage is 10V and two resistances are 2 ohm and 3 ohm respectively.

a) When two resistors are connected in series combination, the combined resistance given by them would be (2+3)ohm = 5ohm.

b) We know that the amount of voltage = Amount of current passed × Resistance given.

So , I = V/ R

I = 10/5 [ combining resistance of two resistors in series combination, 2+3 =5]

Therefore I = 2 amp.

c) At 2 ohm resistor, the potential difference is :

V= I×R

So, 2×2= 4V.

d) At 3 ohm resistor, the potential difference is:

V= 2×3

=6V

Answer 2

Answer:

Explanation:

a.) Combined Resistance,  

b.) As per Ohm's Law, V = IR

or I =  

=  2 A

c.) Potential Difference across the  

=  = 4 V

d.) Potential Difference across the  

=  = 6 V