Question 3.6 Write the atomic number of the element present in the third period and seventeenth group of the periodic table.
Class XI Classification of Elements and Periodicity in Properties Page 93
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111
element presents in the 3rd period and 17th Group of the periodic table.
we know,
period of element = principal quantum number of that element in which last electron enters .
3rd period = principal quantum number( n)
hence, n = 3
element presents in 17th group .but we know, General configuration of 17th Group is ns², np⁵. Here, n = 3
it means General electronic configuration of element is 3s², 3p⁵.
so, complete electronic configuration of element is 1s², 2s², 2p⁶, 3s², 3p⁵.
total number of electrons in Ground state of elements = 2 + 2 + 6 + 2 + 5 = 17
but we know,
number of electron = atomic number { for neutral atom }
hence, atomic number of element = 17
we know,
period of element = principal quantum number of that element in which last electron enters .
3rd period = principal quantum number( n)
hence, n = 3
element presents in 17th group .but we know, General configuration of 17th Group is ns², np⁵. Here, n = 3
it means General electronic configuration of element is 3s², 3p⁵.
so, complete electronic configuration of element is 1s², 2s², 2p⁶, 3s², 3p⁵.
total number of electrons in Ground state of elements = 2 + 2 + 6 + 2 + 5 = 17
but we know,
number of electron = atomic number { for neutral atom }
hence, atomic number of element = 17
Answered by
11
Answer:
17
Explanation:
n=3,that indicates 3rd period
17th group
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