Question

Question 3
Evaluate: ſ esin x sin 2xdx.​

Answer 1

Answer:

We know that sin 2x = 2 sin x cos x So we get ∫esin x sin 2x dx = 2 ∫esin x sin x cos x dx Take sin x = t So we get cos x dx = dt It can be written as 2 ∫ esin x sin x cos x dx = 2 ∫ et t dt Consider first function as t and second function as et By integrating w.r.t. t = 2 (t et – ∫1. et dt) We get = 2 (t et – et) + c Here = 2 et(t – 1) + c By substituting the value of t = 2 esin x(sin x – 1) + CRead more on Sarthaks.com - https://www.sarthaks.com/822979/evaluate-the-integral-e-sin-x-sin-2x-dx

Answer 2

Answer:

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