Question

Question 3 What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10 24 kg and radius of the earth is 6.4 × 10 6 m).

Class 9 - Science - Gravitation Page 143

Answer 1

gravitational force = Gm₁m₂/r²
    here 
       m₁ = 6 × 10²⁴ Kg
       m₂ = 1 Kg
       r     = 6 × 10⁶ m
now, force = 6.67 × 10⁻¹¹ × 6 ×10²⁴ ×1/(6.4×10⁶)²
                   =6.67 × 6 ×10/(6.4)²
                   =9.77 N

Answer 2

_/\_ Hello mate__ here is your answer -

Mass of Earth, M = 6 × 10^24 kg

Mass of object, m = 1 kg

Universal gravitational constant,

G = 6.7 × 10^−11 Nm^2 kg^−2

r = radius of the Earth (R) ( ob. is on the surface of earth)

r = R = 6.4 × 10^6 m

Therefore, the gravitational force

F = GMm / r^2

= (6.7×10^-7×6×10^24 ×1)/(6.4×10^4)^2

= 9.8 N

I hope, this will help you.☺

Thank you______❤

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