Question 3 What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10 24 kg and radius of the earth is 6.4 × 10 6 m).
Class 9 - Science - Gravitation Page 143
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Answered by
17
gravitational force = Gm₁m₂/r²
here
m₁ = 6 × 10²⁴ Kg
m₂ = 1 Kg
r = 6 × 10⁶ m
now, force = 6.67 × 10⁻¹¹ × 6 ×10²⁴ ×1/(6.4×10⁶)²
=6.67 × 6 ×10/(6.4)²
=9.77 N
here
m₁ = 6 × 10²⁴ Kg
m₂ = 1 Kg
r = 6 × 10⁶ m
now, force = 6.67 × 10⁻¹¹ × 6 ×10²⁴ ×1/(6.4×10⁶)²
=6.67 × 6 ×10/(6.4)²
=9.77 N
Answered by
2
_/\_ Hello mate__ here is your answer -
Mass of Earth, M = 6 × 10^24 kg
Mass of object, m = 1 kg
Universal gravitational constant,
G = 6.7 × 10^−11 Nm^2 kg^−2
r = radius of the Earth (R) ( ob. is on the surface of earth)
r = R = 6.4 × 10^6 m
Therefore, the gravitational force
F = GMm / r^2
= (6.7×10^-7×6×10^24 ×1)/(6.4×10^4)^2
= 9.8 N
I hope, this will help you.☺
Thank you______❤
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