Question

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Answer 1

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Answer 2

$\huge{\boxed{question}}$

In Fig. 6.41, if AB l l DE, ∠BAC = 35° and ∠CDE = 53°, find ∠DEC

$\huge{\boxed{\boxed{\red{\boxed{\underline{\green{Solution}}}}}}}$

$\large{\boxed{\underline{\underline{Given}}}}$

AB l l to DE,

∠BAC = 35°

∠CDE = 53°

To find , ∠DCE

According to the question

∠BAC = ∠CDE. (alt int. Angle)

Therefore,

∠CED = 35°

Now in triangle DEC

∠DCE + ∠CED + ∠CDE = 180° (Sum of the interior angles of the triangle)

=> ∠DCE + 35° + 53° = 180°

=>∠DCE + 88° = 180°

=>∠DCE = 180° - 88°

=> ∠DCE = 92°