"Question 3 Work out the following divisions. (i) (10x − 25) ÷ 5 (ii) (10x − 25) ÷ (2x − 5) (iii) 10y(6y + 21) ÷ 5(2y + 7) (iv) 9x^2y^2(3z − 24) ÷ 27xy(z − 8) (v) 96abc(3a − 12)(5b − 30) ÷ 144(a − 4) (b − 6)
Class 8 Factorisation Page 227"
Answers
Factors:
In a product of two or more expressions each expression is called a factor of the product.
Factorization:
The process of writing a given expression as a product of two or more factors is called factorization.
Division of a monomial by monomial:
To divide one monomial by another divide the numerical coefficient of the dividend by the numerical coefficient of the divisor and the powers of variables in the dividend by the corresponding powers in the divisor then multiply all the quotients.
Division of a polynomial by a monomial:
To divide a polynomial by a monomial divide each term of the polynomial by the monomial and then add all the partial quotients thus obtained.
Division of a polynomial by a binomial by factor method:
In this case we factorise the dividend. One of the factors will be equal to divisior which is a binomial. We then cancel the common factor assuming that the divisor is not equal to zero and obtain the answer.
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Solution:
1)
(10x – 25) ÷ 5
=5(2x-5)/5
=(2x-5)
2) (10x – 25) ÷ (2x – 5)
= 5(2x-5) /(2x – 5)
=5
3) 10y(6y + 21) ÷ 5(2y + 7)
10y × 3(2y+7)÷ 5(2y + 7)
=30y(2y+7)/ 5(2y + 7)
= 6y
4) 9x²y² (3z – 24) ÷ 27xy(z – 8)
9x²y²× 3 (z – 8) ÷ 27xy(z – 8)
=27 x²y²(z- 8)/ 27xy(z – 8)
=xy
5) 96abc(3a – 12) (5b – 30) ÷ 144(a – 4) (b – 6)
=(96×3×5)abc(a-4)(b-6)/ 144(a – 4) (b – 6)
=10abc
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Hope this will help you....
Answer
Step-by-step explanation: