Question

QUESTION 3)You are given three bags and cards of fractions.
BAG 1: AVENGERS- It contains CARDS WITH FRACTIONS LESS THAN 1

BAG 2 : MINION -It contains CARDS WITH FRACTIONS EQUAL TO 1

BAG 3: DORAEMON: It contains CARDS WITH FRACTIONS GREATER THAN 1

CARDS : 3/7 , 4/4 , 9/8 , 8/9 , 5/6 , 6/11 , 18/18 , 19/25 , 2/3, 13/17

Based on the above given information answer the following:
(i) Put the right card in the right bag
(ii) What are the fractions in Basg 1 and Bag 3 known as?
(iii) Convert the fractions in Bag 3 to mixed fractions.
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Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Answer 2

Answer:

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