Question 30
(I don't want to get it done by adding two equations method. So, Give Another One)
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sec Ф + tan Ф = p
⇒ 1/cos Ф + sin Ф / cos Ф = p
⇒ ( 1 + sin Ф ) / cos Ф = p
⇒ ( 1 + sin Ф )² / cos² Ф = p²
⇒ ( 1 + sin Ф )² = p² cos²Ф
Use cos²Ф = 1 - sin²Ф :
⇒ ( 1 + sin Ф )² = p² - p² sin²Ф
⇒ 1 + sin²Ф + 2 sin Ф = p² - p² sin²Ф
⇒ sin²Ф + p²sin²Ф + 2 sinФ + 1 = 0
⇒ sin²Ф ( 1 + p² ) + 2 sin Ф + 1 - p = 0
Compare with ax² + bx + c = 0
a = p² + 1
b = 2
c = 1
Using the quadratic formula we can get the value of sin Ф .
cosec Ф = 1/sin Ф
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sec + tan = p
1/cos + sin /cos = p
(sin +1)/cos = p
(sin + 1)^2 /(1 - sin)^2 = p^2
(sin + 1)/ ( 1 - sin ) = p^2
sin + 1 = p^2 - p^2sin
sin + p^2 sin = p^2 -1
sin (1 + p^2) = p^2 - 1
sin = (p^2 -1) / (1+p^2)
cosec = (1 +p^2)/ (1 - p^2)
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