Question

Question 31 please help and give full solution

Answer 1

⭐《QUESTION》

The De- broglie's wavelength of the car of mass 1000 kg and travelling at velocity 36 km/hr will be ?? ( h = 6.63 * 10^-34 Js )

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the ATOMIC STRUCTURE

↪Basically we know that , the De- broglie's wavelength is given as

↪Lambda ( /\) = h / p

↪where , h = planck's Constant and p = linear MOMETUM

↪speed is 36 km/hr. ., in SI UNIT ==》 36 * 5/18 ==》 10 m/s

↪v = 10 m/s

↪so we get here as ,

↪/\ = h / m*v

↪/\= 6.63 * 10^-34 / 1000 * 10

↪/\==》 6.63 * 10^-34 / 10^4

⭐(/\)Lambda = 6.63 * 10^-34 * 10^-4

〽(/\)Lambda = 6.63 * 10^-38 metres

Answer 2

Answer:

the first answer of my friend is correct as per as as I know becz now i am in class 9 only and i don't know how to answer the question of jee but now i am preparing myself for NTSE