Question

Question 33:
If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s2, how long will it take to come to rest ?

Lakhmir Singh Physics Class 9

Answer 1

Distance=20m/s
Acceleration= -5m/s square
Time=?

Now,

$acceleration = \frac{v - u}{t}$
$- 5 = \frac{20 - 0}{?}$
$time = \frac{20}{5} = 4second$

Answer 2

..............................................................................................................✡✡✡
✡ INITIAL VELOCITY ✡ ( U ) = 20 m / s

✡ DEACCELERATION ✡ = 5 m / s^2

✡ - ( ACCELERATION ) ✡ = DEACCELERATION

✡ - ( A ) ✡ = 5 m / s^2

✡ ACCELERATION ✡ = - 5 m / s^2

✡ FINAL VELOCITY ✡ ( V ) = 0 m / s

✡ ACCELERATION ✡ = V - U / T

➡ - 5 = 0 - 20 / T

➡ - 5 = - 20 / T

➡ T = 4 s
..............................................................................................................✡✡✡
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