Question

Question 3x - 4/3y=13​

Answer 1

$given \: that \\ \frac{3x - 4}{3y} = 13 \\ so \: we \: have \: to \: \: find \: the \: values \\ of \: \: x \: \: \: and \: \: y$

$\frac{3x - 4}{3y} = 13 \\ = > 3x - 4 = 13 \times 3y \\ = > 3x - 4 = 39y \\ = > 3x - 39y - 4 = 0 \\ = > 3(x - 13y) - 4 = 0 \\ = > 3(x - 13y) = 4 \\ = > x - 13y = \frac{4}{3} \\ so \: from \: we \: can \: get \: the \: value \\ of \: \: x \: \: and \: \: \: \: y \\ x = \frac{4}{3} + 13y \\ = > x = \frac{4 + 39y}{3} \\ and \\ x - 13y = \frac{4}{3} \\ = > - 13y = \frac{4}{3} - x \\ = > 13y = x - \frac{4}{3} \\ = > 13y = \frac{3x - 4}{3} \\ = > y = \frac{3x - 4}{39}$

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