question 4
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Step-by-step explanation:
Given :
AB = RS
angle ABP = angle SRQ
BQ = PR .....( 1 )
Adding QP both side in equ ( 1 ) we get
BQ + QP = PR + QP
BP = RQ
In ΔABP and ΔRQS
AB = RS (given)
BP = RQ (proved above)
angle ABP = angle SRQ (given)
ΔABP is congruent to ΔRQS by criteria SAS
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