Math, asked by kulwinderanttal08, 11 months ago

question 4
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Answers

Answered by Awani03
1

Step-by-step explanation:

Given :

AB = RS

angle ABP = angle SRQ

BQ = PR .....( 1 )

Adding QP both side in equ ( 1 ) we get

BQ + QP = PR + QP

BP = RQ

In ΔABP and ΔRQS

AB = RS (given)

BP = RQ (proved above)

angle ABP = angle SRQ (given)

ΔABP is congruent to ΔRQS by criteria SAS

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