Question

Question 4.5: What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?

Class 12 - Physics - Moving Charges And Magnetism Moving Charges And Magnetism Page-169

Answer 1

Let I be the length of wire, carrying a current of 8A at an angle 30° with the magnetic field .
force on the wire is given by , F = BILsinθ
so, force per unit length , F/L = BIsinθ

here, B = 0.15 T , I = 8A and θ = 30°
so, Force per unit length = 0.15 × 8 × sin30°
= 1.2 × 1/2 = 0.6 N/m

Answer 2

Answer: 0.6 N/m

Explanation: Image is attached