Question 4.6: A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
Class 12 - Physics - Moving Charges And Magnetism Moving Charges And Magnetism Page-169
Answers
Answered by
11
length of wire, l = 3cm = 0.03 m
current through wire , I = 10A
magnetic field , B = 0.27T
wire is placed inside a solenoid perpendicular to its axis. so, θ = 90°
now, F = BIL sinθ [ from formula]
= 0.27 × 10 × 0.03 × sin90°
= 0.081 N
hence, magnetic force on the wire is 0.081 N
current through wire , I = 10A
magnetic field , B = 0.27T
wire is placed inside a solenoid perpendicular to its axis. so, θ = 90°
now, F = BIL sinθ [ from formula]
= 0.27 × 10 × 0.03 × sin90°
= 0.081 N
hence, magnetic force on the wire is 0.081 N
Answered by
8
Answer: 8.1×10^(-2) N
Explanation: Image is attached
Attachments:
Similar questions