Question 4. Consider the compounds, BCl3and CCl4. How will they’behave with water justify?
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BCl3 is an electron deficient molecule . it easily accepts a pair of electron from water and hence, BCl3 undergoes Hydrolysis to form boric acid (H3BO3) and HCl.
BCl3 + 3H2O --->H3BO3 + 3HCl .
CCl4 is an electron precise molecule having absence of d- orbitals in C-atom and hence, it neither accepts nor donates a pair of electrons . thus, CCl4 doesn't undergo hydrolysis in water.
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