Question 4: Find dy/dx : xy + y2 = tan x + y
Class 12 - Math - Continuity and Differentiability
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★ DIFFERENTIATION ★
Given function has to be resolved in partial differentiation methods aslike ;
xy + y² = tanx + y
δx/δy = y - sec² x
δy/ δx = x + 2y - 1
Now , dy/dx = - (δx/δy) / δy/δx
Sec²x - y / x + 2y - 1
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Given function has to be resolved in partial differentiation methods aslike ;
xy + y² = tanx + y
δx/δy = y - sec² x
δy/ δx = x + 2y - 1
Now , dy/dx = - (δx/δy) / δy/δx
Sec²x - y / x + 2y - 1
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
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