Question 4 Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even?
Class X1 - Maths -Permutations and Combinations Page 148
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Total number of digits = 5 { 1, 2, 3, 4 , and 5 }
—, —, — , —
number of ways to fill the unit place =5
number of ways to fill the ten place = 4
number of ways to fill the hundred place = 3
number of ways to fill the thousand place = 2
hence, by Fundamental principle of counting,
total number of ways = 5 × 4 × 3 × 2
= 120
again,
for even :
number of ways to fill the unit place = 2 { because 2 , 4 can be filled for even number }
number of ways to fill the tenth place = 4
number of ways to fill the hundred place = 3
number of ways to fill the thousand place = 2
by , fundamental principle of counting,
total number of ways = 2 × 4 × 3 × 2 = 48
—, —, — , —
number of ways to fill the unit place =5
number of ways to fill the ten place = 4
number of ways to fill the hundred place = 3
number of ways to fill the thousand place = 2
hence, by Fundamental principle of counting,
total number of ways = 5 × 4 × 3 × 2
= 120
again,
for even :
number of ways to fill the unit place = 2 { because 2 , 4 can be filled for even number }
number of ways to fill the tenth place = 4
number of ways to fill the hundred place = 3
number of ways to fill the thousand place = 2
by , fundamental principle of counting,
total number of ways = 2 × 4 × 3 × 2 = 48
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