QUESTION 4:
Find the values of 'm' so that the equation
(m-4)x² + 2(m-4)x +4 =0 has equal roots.
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Answer:
as the equation has equal roots so,
b^2-4ac=0
here b=2(m-4)
a=(m-4)
c=4
so,
(m-4)^2-4.(m-4).4=0
=> (m-4)^2=16(m-4)
=> m-4=16
=> m=16+4=20
the value of m is 20
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