Question 4
In triangle PQR (given figure) PQ = 4 cm, PR = 8 cm, RT = 6 cm then find :
(i) Area of ∆PQR
(ii) Length of QS
Answers
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Area of triangle is 12cm² and length of QS is 3cm
PQ = 4cm, (Given)
PR = 8cm, (Given)
RT = 6cm (Given)
Area of Triangle = 1/2 × l × b
Area of ΔPQR = 1/2 × RT × PQ
= 1/2 × 6 ×4
= 12
Thus, area = 12cm²
in ΔPQR, RT ⊥ PQ and QS ⊥ PR
Thus,
1/2 × PQ × RT = 1/2 × PS × QS
= PQ×RT = PR × QS
= 4×6 = 8×QS
= 24 = 8×QS
= QS = 3cm
Thus, the length of QS is 3cm
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