Question

Question 4 Write the general term in the expansion of (x^2 – yx)^12, x ≠ 0

Class X1 - Maths -Binomial Theorem Page 171

Answer 1

The General term in the expansion of (X - Y)ⁿ is $T_{r+1}= ^nC_rX^{n-r}(-y)^r\\\\\\Here\:,X=x^2,Y=yx\:and\:n=12$

The general term of (x² - yx)¹² is
$T_{r+1}= ^{12}C_r(x^2)^{12-r}(-yx)^r\\\\= ^{12}C_rx^{24-2r}(-1)^rx^ry^r\\\\= ^12C_r(-1)^rx^{24-2r+r}y^r\\\\= ^{12}C_r(-1)^rx^{24-r}y^r$