Question 40:
A stone is dropped from a height of 20 m.
(i) How long will it take to reach the ground ?
(ii) What will be its speed when it hits the ground ? (g =10 m/s2)
Lakhmir Singh Physics Class 9
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Answer:
Given
u = 0 m/s
g = 10 m/s^2
h = 20 m
Now using
s = ut + 1/2 at^2
that is
h = ut + 1/2 gt^2
Now substitute the value
20 = 0*t + 1/2 * 10 (t)^2
20 = 5(t)^2
(t)^2 = 4
t = 2s
Now again using
V = u + at
V = 0 + 10 * 2
V =20 m/s
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