Math, asked by vaishnavitaneja, 2 months ago

Question 43.Solve: p + 1 = 2(a) 1(b) 2(c) -1(d) -2​

Answers

Answered by TwilightShine
12

Answer :-

  • The correct option is a).
  • The value of p is 1.

Step-by-step explanation :-

Solve the equation :-

 \sf p + 1 = 2

Transposing 1 from LHS to RHS, changing its sign,

 \sf p = 2 - 1

On simplifying,

 \sf p = 1.

So, the value of p is 1.

Verification :-

To check our answer, we just have to put 1 (value of p) in place of p and check whether the LHS = RHS.

Putting 1 in place of p, we get :-

 \sf 1 + 1 = 2

On simplifying,

 \sf 2 = 2.

Since LHS = RHS,

Hence verified! ✔️✔️

Answered by shaktisrivastava1234
133

 \huge \underline{ \rm{Answer}}

 \large \underline{ \underline{ \frak{ \color{peru}Given:}}}

 \mapsto \sf{p + 1 = 2}

 \large \underline{ \underline{ \frak{ \color{green}To \:  find:}}}

 \leadsto \sf{The  \: value  \: of   \: \bf p.}

 \large \underline{ \underline{ \frak{ \color{blue}According \:  to  \: Question:}}}

 \dashrightarrow \sf{p + 1 = 2}

Transposing 1 to R. H. S.

 \dashrightarrow \sf{p  = 2 - 1}

 \dashrightarrow \sf{p  = 1}

 \bf \underline{Hence,}

 \longmapsto \sf{Option \:  (b) \:  is \:  correct.}

 \large \underline{ \underline{ \frak{ \color{indigo}Verification:}}}

 \longrightarrow \sf{p + 1 = 2}

Substituing the values, we get

 \longrightarrow \sf{1+ 1 = 2}

 \longrightarrow \sf{2 = 2}

 \checkmark \sf{L. H. S.=R. H. S. }

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