Question 5.12 A bob of mass 0.1 kg hung from the ceiling of a room by a string 2 m long is set into oscillation. The speed of the bob at its mean position is 1 m s–1. What is the trajectory of the bob if the string is cut when the bob is (a) at one of its extreme positions, (b) at its mean position.
Chapter Laws Of Motion Page 110
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87
In simple harmonic motion, velocity of the body at mean is maximum and extreme position is zero.
(A) according to above explanation, velocity of the bob at extreme position is zero. If the string is cut at extreme position then, bob falls down . hence, motion of trajectory is a vertical straight line .
(B) in mean position velocity of bob is Maximum and it's direction in horizontal .
If cut the string at mean position then the bob will behaves as a horizontal projectile .
Hence, trajectory of the bob will be parabolic .
(A) according to above explanation, velocity of the bob at extreme position is zero. If the string is cut at extreme position then, bob falls down . hence, motion of trajectory is a vertical straight line .
(B) in mean position velocity of bob is Maximum and it's direction in horizontal .
If cut the string at mean position then the bob will behaves as a horizontal projectile .
Hence, trajectory of the bob will be parabolic .
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39
☺Hello frds_____
✒Your answer is here ⤵
(a) Vertically downward, Parabolic path
▶▶▶ At the extreme position, the velocity of the bob becomes zero. If the string is cut at this moment, then the bob will fall vertically on the ground.
(b) At the mean position, the velocity of the bob is 1 m/s. The direction of this velocity is tangential to the arc formed by the oscillating bob. If the bob is cut at the mean position, then it will trace a projectile path having the horizontal component of velocity only.
▶▶Hence, it will follow a parabolic path.
I hope, this will help you
Thank you____❤
✿┅═══❁✿ Be Brainly ✿❁═══┅✿
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