Question

Question 5
(- 2x - 5)(2x - 8) - (2x - 5)(3x + 7)
Question 6
(x2 + 4)(x - 4) - (-x - 1)(6x)
Question 7
(-x3 + 4)(x + 2) - (2x - 1)(5x)
Question 8
(x2 + 5)(x + 5) - 3x2(3x + 1)
Question 9
(x3 + 1)(-2x + 2) + 2x2(4x2 + 1)
Question 10
(x4 - 3)(3x - 4) + 2x3(2x2 - 2)

Answer 1

Step-by-step explanation:

5. (-2x-5)(2x-8)-(2x-5)(3x+7)

= [-4x^2+16x-10x+40]-[6x^2+14x-15x-35]

= [-4x^2+6x+40]-[6x^2-x-35]

=-4x^2+6x+40-6x^2+x+35

=-10x^2+7x+75

6. (x^2+4)(x-4)-(-x-1)(6x)

= [x^3-4x^2+4x-16]-[-6x^2-6x]

= x^3-4x^2+4x-16+6x^2+6x

=x^3+2x^2+10x-16

7.(-x^3+4)(x+2)-(2x-1)(5x)

=[-x^4-2x^3+4x+8]-[10x^2-5x]

=-x^4-2x^3+4x+8-10x^2+5x

=-x^4-2x^3-10x^3+9x+8

8.(x^2+5)(x+5)-3x^2(3x+1)

= [x^3+5x^2+5x+25]-[9x^3-3x^2]

=x^3+5x^2+5x+25-9x^3+3x^2

=-8x^3+8x^2+5x+25

9. (x^3+1)(-2x+2)+2x^2(4x^2+1)

= [-2x^4+2x^3-2x+2]+[8x^4+2x^2]

= -2x^4+2x^3-2x+2+8x^4+2x^2

=6x^4+2x^3+2x^2-2x-2

10. (x^4-3)(3x-4)+2x^3(2x^2-2)

= [3x^5-4x^4-9x+12]+[4x^5-4x^3]

= 3x^5-4x^4-9x+12+4x^5-4x^3

= 7x^5-4x^4-4x^3-9x+12

Hope it will help you

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