The edges of a cube shrink at a rate of 2 centimeters per second. What is the
rate of change of the surface area of the cube when the sides have length 3 centimeters?
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Let the side of cube be a
here,
da/dt = 2 cm/s
now,
let the Area be A
surface area of cube = A
where.
A = 6a²
so,
Rate of shrinking of surface area = dA/dt
= 12a per sec
given side = 3 cm
so,
rate of shrinking of surface area = 12(3) = 36²cm/s
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