"Question 5 A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each cow be getting?
Class 9 - Math - Heron's Formula Page 207"
Answers
Answered by
46
s=30+30+48/2
s=54
area=√54(54-30)(54-30)(54-48)
area=432m²
area×2/18
432×2/18
864/18
48m²
Therefore,every cow will get 48m² to graze
s=54
area=√54(54-30)(54-30)(54-48)
area=432m²
area×2/18
432×2/18
864/18
48m²
Therefore,every cow will get 48m² to graze
Answered by
18
We know that the diagonals of the rhombus bisect each other at right angle .Using Pythagoras theorem ,I have..
________ _______
OD=√AD²-AO² =√30²-24²m
___________
=√【30+24)(30-24)m
______
√54×6m
_______
√9×6×6m
(3×6)m =18m
Area of one triangle AOD=(1/2×24×18)m^2
=216m^2
Area of rhombus =4×∆AOD
= (4×216(m^2=864m^2
Grass area for 18 cows =864m^2
Grass area for 1 cow=864/18=48m^2
Thanks ♥️
________ _______
OD=√AD²-AO² =√30²-24²m
___________
=√【30+24)(30-24)m
______
√54×6m
_______
√9×6×6m
(3×6)m =18m
Area of one triangle AOD=(1/2×24×18)m^2
=216m^2
Area of rhombus =4×∆AOD
= (4×216(m^2=864m^2
Grass area for 18 cows =864m^2
Grass area for 1 cow=864/18=48m^2
Thanks ♥️
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