Question

QUESTION 5: A solution of the linear equation 3x+2y−5=0 is 1 point (2, -3) (1, 2) (5, -5) ( -5, 5)

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Given,

Linear equation

3x + 2y - 5 = 0

Now substituting ( 5 , -5 ) in x and y ,we get

3 ( 5 ) + 2 ( -5 ) - 5 = 0

15 - 10 - 5 = 0

15 - 15 = 0

0 = 0

So , one point is ( 5 , -5 ) is the answer.