Math, asked by praveen2626, 6 months ago

Question 5:
Bus route A starts at the bus station and takes 40 minutes.
Bus route B also starts at the bus station and takes 30 minutes.
Both routes begin at 9am, therefore leave the bus station at the same time.
At what time do both routes leave the bus station at the same time for the fourth time in
the day?
Clive's answer:
Your answer:
The buses leave the station every 2 hours.
So they leave the bus station together for
the fourth time after 8 hours.
9am + 8 hours
Answer:
5pm or 17:00
What mistake has Clive made?​

Answers

Answered by ninjatall12
2

Answer:

Clive did not account for the first time they left together at 9 AM

Step-by-step explanation:

Since they both left at 9 am that was the first time they left at the same time so the fourth time should 360 min which is 6 hours 9 am+6 hours=15:00 or 3PM.

Answered by amitnrw
0

Given: Bus route A starts at the bus station and takes 40 minutes.

Bus route B also starts at the bus station and takes 30 minutes.

Both routes begin at 9am

To Find : At what time do both routes leave the bus station at the same time for the fourth time in the day?

Solution:

Bus route A starts at the bus station and takes 40 minutes.

Bus route B also starts at the bus station and takes 30 minutes.

Both will leave at the same time again LCM (40 , 30)

40 = 2 * 2 * 2 * 5

30 = 2 * 3 * 5

LCM = 2* 2 *2 * 3 * 5  = 120

120 mins = 2 hrs

Buses leave together every 2 hrs

Buses leaves for 1st time at 9 : 00 AM

Buses leaves for 2nd time at 11 : 00 AM

Buses leaves for 3rd time at  1: 00 PM

Buses leaves for 4th time at  3 : 00 PM

Mistake made by Clive was that he ignored that Buses left 1st time at 9 :00 AM itself

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